slove it urgent 9th no.
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sum of angles of a quadrilateral = 360°
therefore,a+b+c+d=360°
a+b+100°+60°=360
a+b+160°=360°
a+b=360°-160°
a+b=200°
IT IS A EQUILATERAL TRIANGLE
SO,200°/2=100 °
so,angle pab=100°,angle pba=100°and
angle apb=100°
therefore,a+b+c+d=360°
a+b+100°+60°=360
a+b+160°=360°
a+b=360°-160°
a+b=200°
IT IS A EQUILATERAL TRIANGLE
SO,200°/2=100 °
so,angle pab=100°,angle pba=100°and
angle apb=100°
praga04:
i hope this helps you
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search on Google u will be get your answer
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