Question

slove it with clear explanation​

Answer 1

Answer:

$\sqrt{ {(x1 - x2)}^{2} + \: {(y1 - y2)}^{2} } = 10 \\ \sqrt{ {(10 - 2)}^{2} + {(y - ( - 3) )}^{2} } = 10 \\ \sqrt{64 + {y}^{2} + 6y + 9} = 10 \\ {y}^{2} + 6y + 73 = 100 \\ {y}^{2} + 6y - 27 = 0 \\ applying \: quadratic \: formula \\ y = \frac{ - 6 - + \sqrt{36 + 108 } }{2} \\ y = (- 6 - + 12 ) \div 2 \\ y = - 3 - + 6 \\ y = - 9 \: \: or \: \: y = 3$

Therefore y= 3,as distance can't be negative so ignore -9

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Answer 2

Step-by-step explanation:

(2-10)^2+(y+3)^2 =100

64+y^2+9+6y=100

y^2+6y-100+73=0

y^2+6y-27=0

the roots are 3 and -9....

the point y can be either 3 or -9

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