Question

slove it with steps​

Answer 1

Answer:

a)In Triangle ABM & PQN

AB = PQ (Given)

AM = PN (Given)

BM = QN (Given)

therefore,

ABM (Is Congruent to) PQN(SSS RULE)

Also:-<ABM = <PQN (By CPCT) (i)

b)Since M And N Are Median :-

BM = QN & MC = NR

Also:-

BM = QN (Given)

=)2BM = 2QN

=)BC = QR (ii)

Now:-

In ABC & PQR

=)AB = PQ (Given)

<ABM = <PQN (From Equation i)

BC = QR (Given)

Hope it helped

Answer 2

Answer:

Given parameters are:

AB = PQ,

BC = QR and

AM = PN

(i) ½ BC = BM and ½ QR = QN (Since AM and PN are medians)

Also, BC = QR

So, ½ BC = ½ QR

⇒ BM = QN

In ΔABM and ΔPQN,

AM = PN and AB = PQ (As given in the question)

BM = QN (Already proved)

∴ ΔABM ΔPQN by SSS congruency.

(ii) In ΔABC and ΔPQR,

AB = PQ and BC = QR (As given in the question)

ABC = PQR (by CPCT)

So, ΔABC ΔPQR by SAS congruency