Question

slove quadraticby factorization
$2y{2} + 27y + 13 = 0$
​

Answer 1

Answer:

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

Step-by-step explanation:

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

= 12The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x

3

.

So x = \sqrt[3]{1728}

3

1728

The question is to find the cube root of 1728.

An identical number multiplied 3 times will be x^{3}x