Math, asked by kavitprajput, 1 day ago

SLOVE THE EQUATION 2(3x-5/x+2)-5(x+2/3x-5)=3 , where x is not equal to -2 and x is not equal 5/3

Answers

Answered by shoaibmallik1003
0

Answer:

2(3x-5/x+2)-5(x+2/3x-5)=3 ,

Answered by knjroopa
1

Step-by-step explanation:

Given SOLVE THE EQUATION 2(3x-5/x+2)-5(x+2/3x-5) = 3 , where x is not equal to -2 and x is not equal 5/3

  • So we have the equation
  •                           2(3x – 5 / x + 2) – 5 (x + 2 / 3x – 5) = 3
  •           Let 3x – 5 / x + 2 = a
  •       So x + 2 / 3x – 5 = 1/a
  •        Now we get 2a – 5/a = 3
  •                           2a^2 – 5 = 3a
  •                           2a^2 – 3a – 5 = 0
  •                          2a^2 – 5a + 2a – 5 = 0
  •                        a (2a – 5) + 1 (2a – 5) = 0
  •                           (2a – 5) (a + 1) = 0
  •                         So 2a = 5     a = - 1
  •                             a = 5/2 or a = -1
  • Now when a = 5/2 we get
  • 3x – 5 / x + 2 = 5/2
  •    2(3x – 5) = 5(x + 2)
  •     6x – 10 = 5x + 10
  •          x = 10 + 10
  •          x = 20
  • Now when a = - 1, we get
  •   3x – 5 / x + 2 = - 1
  •  3x – 5 = - x – 2
  •        4x = 3
  •         x = 3/4

Reference link will be

https://brainly.in/question/42822376

https://brainly.in/question/43042389

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