SLOVE THE EQUATION 2(3x-5/x+2)-5(x+2/3x-5)=3 , where x is not equal to -2 and x is not equal 5/3
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2(3x-5/x+2)-5(x+2/3x-5)=3 ,
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Step-by-step explanation:
Given SOLVE THE EQUATION 2(3x-5/x+2)-5(x+2/3x-5) = 3 , where x is not equal to -2 and x is not equal 5/3
- So we have the equation
- 2(3x – 5 / x + 2) – 5 (x + 2 / 3x – 5) = 3
- Let 3x – 5 / x + 2 = a
- So x + 2 / 3x – 5 = 1/a
- Now we get 2a – 5/a = 3
- 2a^2 – 5 = 3a
- 2a^2 – 3a – 5 = 0
- 2a^2 – 5a + 2a – 5 = 0
- a (2a – 5) + 1 (2a – 5) = 0
- (2a – 5) (a + 1) = 0
- So 2a = 5 a = - 1
- a = 5/2 or a = -1
- Now when a = 5/2 we get
- 3x – 5 / x + 2 = 5/2
- 2(3x – 5) = 5(x + 2)
- 6x – 10 = 5x + 10
- x = 10 + 10
- x = 20
- Now when a = - 1, we get
- 3x – 5 / x + 2 = - 1
- 3x – 5 = - x – 2
- 4x = 3
- x = 3/4
Reference link will be
https://brainly.in/question/42822376
https://brainly.in/question/43042389
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