Math, asked by asharafmansuri2, 11 months ago

Slove the equation. 2x^2+4x-60=0 by completing method square

Answers

Answered by tejasgupta
2

Answer:

\boxed{\underline{\boxed{x = -1 \pm \sqrt{31}}}}

Step-by-step explanation:

2x^2 + 4x - 60 = 0\\\\\implies 2(x^2 + 2x - 30) = 0\\\\\implies x^2 + 2x - 30 = 0 \div 2 = 0\\\\\implies x^2 + 2x - 30 = 0\\\\\implies (x^2) + 2(x)(1) = 30\\\\\text{Adding $1^2$ on both sides, we get:}\\\\(x^2) + 2(x)(1) + (1)^2 = 30 + (1)^2\\\\\implies (x+ 1)^2 = 30 + 1 = 31\\\\\implies x + 1 = \pm \sqrt{31}\\\\\implies \boxed{\underline{\boxed{x = -1 \pm \sqrt{31}}}}

Answered by kantekarpavan12345
0

Question:-⬇️

Slove the equation. 2x^2+4x-60=0 by completing method square

Answer:-⬇️

[tex]\boxed{\underline{\boxed{x = -1 \pm \sqrt{31}}}}[/tex]

\boxed{\underline{\boxed{x = -1 \pm \sqrt{31}}}}Step-by-step explanation:

\boxed{\underline{\boxed{x = -1 \pm \sqrt{31}}}}Step-by-step explanation:2x^2 + 4x - 60 = 0\\\\\implies 2(x^2 + 2x - 30) = 0\\\\\implies x^2 + 2x - 30 = 0 \div 2 = 0\\\\\implies x^2 + 2x - 30 = 0\\\\\implies (x^2) + 2(x)(1) = 30\\\\\text{Adding $1^2$ on both sides, we get:}\\\\(x^2) + 2(x)(1) + (1)^2 = 30 + (1)^2\\\\\implies (x+ 1)^2 = 30 + 1 = 31\\\\\implies x + 1 = \pm \sqrt{31}\\\\\implies \boxed{\underline{\boxed{x = -1 \pm \sqrt{31}}}}

❣️Hope this help you ❣️

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