slove the equation cos2A =√5+1/4 A belong to 0,2π
raveesh255:
its /5+1/4 or (/5+1)/4...please confirm that
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cos2A = ( √5 + 1)/4
we know,
( √5 + 1)/4 = cos36° = cosπ/5
cos2A = cosπ/5
2A = 2nπ ± π/5
A = nπ ± π/10
A = π/10 , 11π/10 , in [ 0, 2π ]
hence, two values of A in [ 0, 2π ]
and value of 2A in [ 0, 2π ] is only one
we know,
( √5 + 1)/4 = cos36° = cosπ/5
cos2A = cosπ/5
2A = 2nπ ± π/5
A = nπ ± π/10
A = π/10 , 11π/10 , in [ 0, 2π ]
hence, two values of A in [ 0, 2π ]
and value of 2A in [ 0, 2π ] is only one
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