Question

slove the exponential equation-
${ \sqrt{6} }^{x - 2} = 1$
please with full process​

Answer 1

Answer:

Step-by-step explanation:

Given : ( √6 )^[ x - 2 ] = 1

From the identities of indices, we know that any number having 0 in its power is directly equal to 1.

Therefore, writing 1 as ( √6 )^0.

From the identities of indices, we know that when bases are equal ( with some power on them ), power are also equal.

∴ x - 2 = 0

⇒ x - 2 + 2 = 0 + 2

⇒ x = 2

Hence, the value of x is 2.

Answer 2

Answer:

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