Question

slove the following equation using cramer rule.
x+y-z=0;x+y+3z=9;x-y+z=2​

Answer 1

Step-by-step explanation:

Δ=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

−1

1

−1

3

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=2(1+1)−(−1)(1−1)+3(−2)=4−6=−2

Now, Δ

x

=

∣

∣

∣

∣

∣

∣

∣

∣

9

6

2

−1

1

−1

3

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=14

Δ

y

=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

9

6

2

3

1

1

∣

∣

∣

∣

∣

∣

∣

∣

=−2

Δ

z

=

∣

∣

∣

∣

∣

∣

∣

∣

2

1

1

−1

1

−1

9

6

2

∣

∣

∣

∣

∣

∣

∣

∣

=−6

So,According to Cramer's Rule x=

Δ

Δ

x

=

−2

14

=−7

y=

Δ

Δ

y

=

−2

−2

=1

z=

Δ

Δ

z

=

−2

−6

=3

Answer 2

Answer:

3 is the correct answer may be