Question

slove the following equation Z/2+Z/3-Z/6=8​

Answer 1

Answer:

z=12 please mark it as brainliest and thank even follow if possible

Answer 2

$\huge{\underline{\mathfrak{Answer:-}}}$

we have to solve equation,z/2+z/3-z/6=8

Taking LCM of denominators of (z/2),(z/3) and (z/6)

or LCM of {2,3,6} = 6

now write each fraction in such a way that denominator of it will be 6

i.e, z/2= (3×z)/(3×2)= 3z/6

z/3= (2×z) /(2×3) = 2z/6

z/6= (1×z)/(1×6)= z)6

now,z/2+z/3-z/6 is converted into (3z/6+2z/6-z/6)

so ,(3z/6 + 2z/6 - z)/6 =8

or,(3z+2z-z)/6=8

or,(5z-z)/6=8

or,4z/6=8

or,Z=12

Hence value of Z=12