Question

slove the following equations by trail and error method 5m=15​

Answer 1

By ysing trial and error method:

LHS = 5m

now, put m=1

so, 5m = 5×1 = 5 not equal to 15

put, m=2

so, 5m = 5×2 = 10 not equal to 15

put, m=3

so, 5m= 5×3 = 15 equal to 15.

Hence, m=3

Answered by GauthMath.