Math, asked by Saladitataji, 1 year ago

Slove the following equations for x,y not equals to 0;3x+2y=9xy;9x+4y=21xy

Answers

Answered by Anonymous
3
here is your answer by Sujeet,
3x+2y=9xy
express the equation in simple form,
3x+2y/xy=9

3/y+2/x=9 ________(3)


9x+4y=21xy
9x+4y/xy=21
9/y+4/x=21 ___________(4)
let to be 1/x=a
let to be 1/y=b

solve this question by elimination method,
3b+2a=9. *9
9b+4a=21. *3

27b+18a=81
27b+12a=61

__________
6a=20
a=20/6=10/3
a=10/3

Now solving the equation,
3b+2b=9
3b+2(10/3)=9
b=7/9

Again,
now putting the value of the,
1/x=a
1/x=10/3
x=3/10

Again,
1/y=7/9
y=9/7


that all

Sujeet




Saladitataji: I think this answer is wrong.. Because I have checked in merintation and Google the answer is x=1÷3 and y=1.but u have tried it so I have rated 5stars.....TQ
Answered by Anonymous
0

Answer:

3x+2y = 9xy (1)

9x+4y = 21xy. (2)

Multiply (1) with 3

9x+6y = 27xy (3)

Subtract (2) from (3) we get

2y = 6xy

x = 1/3

Putting value of x in (1)

3(1/3) + 2y = 9(1/3)y

1+2y = 3y

1 = y

Therefore x = 1/3 and y = 1

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