Question

slove the following figers​

Answer 1

Answer:

In the first figure:

let 50⁰ be =angle a

let 130° be =angle b

let 120° be =angle c

let x=angle c or x

sum of all the angles of a quadrilateral=360⁰

a+b+c+x=360⁰

50⁰+130⁰+120⁰+x=360⁰

300⁰+x=360⁰

x=360⁰-300⁰

x=60⁰

In the second figure:

let 70⁰=angle a

let 60⁰=angle b

let 90⁰= angle c

let x = angle x or d

a+b+c+x=360⁰

70⁰+60⁰+90⁰+x=360⁰

220⁰+x=360⁰

x=360⁰-220⁰

x=140⁰

HOPE IT WILL HELP YOU AND IF YOU WANT TO CHECK THE ANSWER YOU CAN PUT THE FOLLOWING VALUES OF X AND CAN CHECK IF BOTH SIDES I.E., L.H.S.=R.H.S.