Question

slove the following hello ​

Answer 1

Answer:

do it by yourself

Step-by-step explanation:

do it by yourself

Answer 2

Answer:

4x² - 1 = 0

by comparing with ax² + bx +c = 0

a= 4 b = 0 , c = -1

by using shri Dharacharya method

$\sf - b \: ± \frac{ \sqrt{ {b}^{2} - 4ac} }{2} \\\sf = - 0 ± \frac{ \sqrt{ {0}^{2} - 4(4)( - 1) } }{2} \\ \sf = 0± \frac{ \sqrt{16} }{2} \\ \sf \: = ±\frac{4}{2} \\ \sf = ±2$

${\underline{\color{teal}{\textsf{\textbf{~so ~the~ roots~ are~ +2, ~-2}}}}}$