Question

slove the following pair of equations by elimination method 2x+3y=12 and 3x+2y=13​

Answer 1

X=3,y=2

Step-by-step explanation:

so the answer is x=3,y=2

Answer 2

Answer:   x = 3, y = 2

Hiii...

2x + 3y = 12

3x + 2y = 13

Now to eliminate x, we need to make the value next to x the same, so we can multiply the first equation by 3 and multiply the second equation by 2

6x + 9y = 36

6x + 4y = 26

Now we will subtract the first equation from the second

(6x - 6x) + (4y - 9y) = (26-36)

0 + (-5y) = (-10)

-5y = -10

5y = 10              (when there is 2 negative sign, it becomes positive)

y = 10/5

y = 2

Now that we have y, we can substitute it in any of the equations

2x + 3y = 12

2x + 3(2) = 12

2x + 6 = 12

2x = 12 - 6

2x = 6

x = 6/2

x = 3

Therefore, the value of x is 3 and the value of y is 2

x = 3

y = 2

Hope this was easy to follow

I hope we come across each other again

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