Question

slove the following pair of linear equations graphically 5x-4x+8=0 and 7x+6y -9=0​

Answer 1

Answer:

5x-4y+8=0 be equation 1st.

7x+6y-9=0 be equation 2nd.

solve these two equations to find the intersection point of these two equations

5x-4y=-8 be equation 1st.

7x+6y=9 be equation 2nd.

multiply 1st equation by 3 and multiply 2nd equation by 2 to get the coefficient of y equal ( elimination method to solve x and y)

5x(3)-4y(3)=-8×3

7x(2)+6y(2)=9×2

15×-12y=-24 equation 3rd.

14x+12y=18 equation 4th.

add these two equations

15x+14x-12y+12y=-24+18

29x=-6

x=-6/29

substitute x=-6/29en equation 1st 5x-4y=-8

5(-6/29)+-4y=-8

4y=(30/29)-8

4y=(30-29×8)/29

4y=-202/29

2y=-101/29

y=-101/58

we get the value of x and y now on representing these two line on graph.