Question

slove the following pair of linear equations using substitution method 2x-y=5 3x+2y=11​

Answer 1

Answer:

x=2 & y=1

Step-by-step explanation:

2x + y = 5 …(i)

3x – y = 5 …(ii)

Adding equations (i) and (ii),

2x + y = 5 + 3x – y = 5

5x = 10

∴ x = 10/5

∴ x = 2

Substituting x = 2 in equation (i),

2(2) + y = 5 4 + y = 5

∴ y = 5 – 4 = 1

∴ (2, 1) is the solution of the given equations.

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Answer 2

Answer:

Step-by-step explanation:

Solve 2x - y = 5 and 3x + 2y = 11 by substitution.

The given two equations are

2x – y = 5 …..(I)

3x + 2y = 11 ….(II)

Multiplying (I) with 2 we get

4x – 2y = 10 ….(III)

Adding (II) with (III)

7x = 21

x = 3

Putting the value of x in (I) we get

2 × 3 − y = 5

⇒ 6 − y = 5

⇒ y=1