Question

Slove the following problem​

Answer 1

Answer:

what should we do? these are only the wages...not a proper question.

post again with full question...

Answer 2

To Find :- using tally marks make a frequency table with intervals as 800 - 810 , 810 - 820 and so on ?

Solution :-

from image we get,

→ Number of workers whose salary is between 800 and 810 = 804, 806, 808 = Total 3

→ Number of workers whose salary is between 810 and 820 = 810, 812 = Total 2

→ Number of workers whose salary is between 820 and 830 = 820 = Total 1

→ Number of workers whose salary is between 830 and 840 = 830, 832, 833, 835, 835, 835, 835, 836, 836 = Total 9

→ Number of workers whose salary is between 840 and 850 = 840, 840, 840, 845, 845 = Total 5

→ Number of workers whose salary is between 850 and 860 = 855 = Total 1

→ Number of workers whose salary is between 860 and 870 = 860, 868, 869 = Total 3

→ Number of workers whose salary is between 870 and 880 = 878 = Total 1

→ Number of workers whose salary is between 880 and 890 = 885 = Total 1

→ Number of workers whose salary is between 890 and 900 = 890, 890, 890, 898 = Total 4 .

now, in tally marks , using ,

• 1 = I
• 2 = II
• 3 = III
• 4 = IIII
• 5 = ||||\ { 4 vertical lines and 1 diagonal line .}

therefore, required frequency table is :-

wages -------- Frequency ------- Tally Marks

800-810 ----------- 3 ------------------------ III

810-820 ----------- 2 ------------------------ II

820-830 ----------- 1 ------------------------ I

830-840 ----------- 9 ------------------------ IIII\IIII

840-850 ----------- 5 ------------------------ IIII\

850-860 ----------- 1 ------------------------ I

860-870 ----------- 3 ------------------------ III

870-880 ----------- 1 ------------------------ I

880-890 ----------- 1 ------------------------ I

890-900 ----------- 4 ------------------------ IIII

⅀ = 30

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