Question

slove the given pair of equations using substitution method 3x+2y=8, 2x-3y =1​

Answer 1

Answer:

⇒ 3x + 2y = 8 ... 1

⇒ 2x - 3y = 1... 2

Multiply eq 1 by 2 and eq 2 by 3

⇒ 6x + 4y = 16 ... 3

⇒ 6x - 9y = 3

i.e. 6x = 3 + 9y ... 4

Substitute eq 4 in eq 3

3 + 9y + 4y = 16

⇒ y = 1

Substitute in eq 4

⇒ x = 12