Question

slove the pair of linear equations 2x+y=7 and 3x-y=8​

Answer 1

Answer:-

The Required values of x and y are 3 and 1 respectively.

Explanation:-

Given:-

• Pair of equations:-

• 2x+y = 7...(1).
• 3x - y = 8...(2)

To Find:-

• The values of x and y.

Now,

By adding both the equations we get:-

↦ (2x + y) + (3x - y) = 7 + 8.

↦ 2x + y + 3x - y = 15.

↦ 5x = 15.

↦ x = 15/5.

↦ x = 3.

So we get the value of x = 3.

So,

By putting the value of x in eq(1) we get,

↦ 2x + y = 7.

↦ 2(3) + y = 7.

↦ 6 + y = 7.

↦ y = 7 - 1.

↦ y = 6.

Therefore the required value of y is 1.

And Hence,

The Required values of x and y are 3 and 1 respectively.

Answer 2

✡ ANSWER ✡

➡ x= 3

➡ y = 1

✡ Given ✡

2x + y = 7 ......... Equation no (1)

3x - y = 8 ......... Equation no (2)

✡ Solution ✡

Now, Adding [eqn.1] from [eqn.2] :-

=> (2x+y) + (3y-8) = 7+8

=> 2x + y + 3y - y = 15

=> 2x + 3x = 15

=> 5x = 15

=> x = $\dfrac{15}{5}$

=> x = $\bold{\large{\fbox{\color{blue} {3}}}}$

▶ Again,

Putting the value of x = 3 in the equation no 1 we get,

=> 3x - y = 8

=> 3(3) - y = 8

=> 9 - y = 8

=> -y = 8-9

=> -y = -1

=> y = $\bold{\large{\fbox{\color{blue} {1}}}}$

Hence, the value of x = 3 and y = 1

Step-by-step explanation:

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