Question

Slove the pair of simultaneous equation y=8-x 2x^2+xy=-16

Answer 1

Answer:

-4

Step-by-step explanation:

if y=8-x

and 2x^2+xy=-16

first substitute the value of y in second equation

2x^2+x(8-x)=-16

2x^2+8x-x^2=-16

x^2+8x=-16

apply quadratic equation

x^2+8x+16=0

apply quadratic equation formula

-8+-√8*8-4*1*16/2*1

-8+-√64-64/2

-8+0/2=-4