Question

slove the quadratic equaton x²-4x-3 =0​

Answer 1

Answer:

answer is 3 and 1

Step-by-step explanation:

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Answer 2

Given :-

$x^2-4x-3 =0$

Required to find :-

x values

How to do it ?

$a=1\\b=-4\\c=-3$

$x=\frac{-b±\sqrt{b^2-4ac} }{2a}$

  $= \frac{4±\sqrt{16+12}} {2a} \\=2±\frac{\sqrt{28} }{2} \\=2±\frac{2\sqrt{7} }{2} \\=2+\sqrt{7}$

       or

     $2-\sqrt{7}$