slove the question class 10
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here, u=-15cm, f=12cm, h1=2cm,v=?,h2=?
using lens formula,
1/f=1/v-1/u
1/v=1/12+1/(-15)
1/v=1/60
v=60cm
hence, magnification=v/u
60/-15=h2/2
=h2=-8cm
hence , image formed us real and inverted.
-ve sign shows the inverted image .
hence, the size of image is 8cm
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