slove the question number 7
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rest solve.......thats easy friend......
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ram4441:
thanks bro.
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n. volume of a brick = volume of the pile.
Therefore n( no. of bricks ) = Volume of pile / Volume of brick
= 500 x 200 x 150 / 20 x 8 x 4
= 46875 / 2 = 23437.5
Thus, 23437 bricks can be loaded safely without any breaking
Therefore n( no. of bricks ) = Volume of pile / Volume of brick
= 500 x 200 x 150 / 20 x 8 x 4
= 46875 / 2 = 23437.5
Thus, 23437 bricks can be loaded safely without any breaking
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