Question

slove the system of liner equation x+ 3y =16 and 2x-y = 4 by substitution method​

Answer 1

Correct Question-:

• Slove the pair of liner equation x+ 3y =16 and 2x-y = 4 by substitution method .

AnswEr-:

• The value of x is 4 .
• The value of y is 4 .

Explanation-:

We have ,

• x + 3y = 16 as [ Equation 1]
• 2x -y = 4 as [ Equation 2]

In Equation 1 -:

• x + 3y =16
• x = 16 - 3y .

By this -: x = 16 - 3y ____________[3]

Substituting x = 16 - 3y in Equation 2 .

• Equation 2 = 2x - y = 4 [ x = 16 - 3y]
• 2( 16 - 3y ) - y = 4
• 32 - 6y - y = 4
• -6y - y = 4 - 32
• -7y = -28
• y = -28 / -7 [ - sign will eliminated]
• y = 28 /7
• y = 4

Therefore,

• y = 4

Substituting y = 4 in [3]

we get ,

• x = 16 - 3(4)
• x = 16 - 12
• x = 4

Therefore,

• x = 4

Hence ,

• The value of x is 4 .
• The value of y is 4 .

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