Math, asked by rahulgupta100008, 1 year ago

slove this content quality guys please

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Answers

Answered by Atharvadharmik
1
√2x^2+2x+5x+5√2=0
√2x(x+√2)+5(x+√2)=0
(√2x+5)(x+√2). =0

=>X=-5/√2 or x=-√2
Hope this helps you!!
Answered by ria113
2
Hey bro !!

Here is your answer...

  \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2}  = 0 \\  \\  \sqrt{2}  {x}^{2}  + 2x + 5x + 5 \sqrt{2}  = 0 \\  \\    \sqrt{2} x(x +  \sqrt{2} ) + 5(x +  \sqrt{2} )  = 0\\  \\   ( \sqrt{2} x + 5)(x +  \sqrt{2} )  = 0\\  \\  x = ( \frac{ - 5}{ \sqrt{2} } ) \:  \: or \:  \:  \: x = ( -  \sqrt{2} ) \\  \\
Hope it helps you...

THANKS
^-^

ria113: thanks 4 brainliest ^-^
rahulgupta100008: how you write
rahulgupta100008: means which keyboard you use
ria113: by keyboard
rahulgupta100008: to write maths equation
rahulgupta100008: Which keyboard ji?
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