Slove this equation (5-2x)^3-(5+2x)^3
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X=0;
expand the two cubic independently,
you'll get :
-300x-16(x)^3;
solving it you'll get one x=0 & other x=√- 75/4;
assuming x belongs to Real number we take x=0.
hope it'll help u
expand the two cubic independently,
you'll get :
-300x-16(x)^3;
solving it you'll get one x=0 & other x=√- 75/4;
assuming x belongs to Real number we take x=0.
hope it'll help u
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