Question

slove this equation 7x+6y(1750+3x)=3800x5​

Answer 1

Answer:

7x+6y=3800 ---- (i)

7x+6y=3800 ---- (i)3x+5y=1750 ---- (ii)

7x+6y=3800 ---- (i)3x+5y=1750 ---- (ii)Multiplying (i) by 5 and (ii) by 6, we get

7x+6y=3800 ---- (i)3x+5y=1750 ---- (ii)Multiplying (i) by 5 and (ii) by 6, we get35x+30y=19000 ---- (iii)

7x+6y=3800 ---- (i)3x+5y=1750 ---- (ii)Multiplying (i) by 5 and (ii) by 6, we get35x+30y=19000 ---- (iii)$$18x + 30y = 10500$$ ---- (iv)

7x+6y=3800 ---- (i)3x+5y=1750 ---- (ii)Multiplying (i) by 5 and (ii) by 6, we get35x+30y=19000 ---- (iii)$$18x + 30y = 10500$$ ---- (iv)Subtracting (iv) from (iii), we get

7x+6y=3800 ---- (i)3x+5y=1750 ---- (ii)Multiplying (i) by 5 and (ii) by 6, we get35x+30y=19000 ---- (iii)$$18x + 30y = 10500$$ ---- (iv)Subtracting (iv) from (iii), we get (35x+30y)−(18x+30y)=1900−10500

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