slove this maths method
( 1 + √8 ) + ( 1 - 2√2 )
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2
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hey mate your question is wrong .
the answer is (-7) according to if the question is:
(1 + √8)×(1-2√2)
= ( 1 + √8 ) × ( 1 - 2√2 )
= ( 1 + √2×2×2 ) × ( 1 - 2√2 )
= (1 + 2√2) × (1 - 2√2)
= using identity (a + b)(a-b) = a^2 - b^2
(1)^2 - (2√2)^2
= 1 - 8
= (-7) Answer
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hope this helps you
yash66527:
your answer is wrong
Answered by
1
(1 + √8) + (1 - 2√2)
= (1 + 2√2) + (1 - 2√2). [LCM of 8- 2×2×2]
Now by Identity: (a+b) (a-b) = a² - b²
(1 + 2√2) + (1 - 2√2)
= ( 1 )² - (2√2)² [a= 1 ; b= 2√2]
= 1 - 4(2)
= 1 - 8
= -7
= (1 + 2√2) + (1 - 2√2). [LCM of 8- 2×2×2]
Now by Identity: (a+b) (a-b) = a² - b²
(1 + 2√2) + (1 - 2√2)
= ( 1 )² - (2√2)² [a= 1 ; b= 2√2]
= 1 - 4(2)
= 1 - 8
= -7
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