Question

slove this problem
cos²B ( 1+ tan²B)=

Answer 1

Step-by-step explanation:

$1 + {tan}^{2} \beta = {sec}^{2} \beta \\ \\ { \cos }^{2} \beta \times {sec}^{2} \beta = 1$

Answer 2

Answer:

$\text {cos²B ( 1+ tan²B)=1}$