Question

Slove this quadratic equations X³+3X²+2X=289

Answer 1

Answer:

5.66 aprox

Step-by-step explanation:

X^3 + 3X^2 + 2X

X^3 + 2X^2 +X^2 + 2X

X^2(X+2) +X(X+2)

(X^2 + X) (X+2)

X(X+1)(x+2) = 289

Solving X = 5.66 approx