Question

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Answer 1

Answer:

That was sooo easy!

HERE IS YOUR ANSWER BUDDY!

Step-by-step explanation:

Given 

cosecθ+cotθ=k __(1)

we know cosec2θ−cot2θ=1

(cosecθ+cotθ)(cosecθ−cotθ)=k

⇒(k)(cosecθ−cotθ)=1

cosecθ−cotθ=k1 __(2)

subtract eq (2) from (1) we get

2cotθ=k−k1⇒sinθ2cosθ=kk2−1 __(3)

Add eq (1) & (2) we get

2cosecθ=k+k1

sinθ2=kk2+1 __(4)

Now from (3) & (4) we can write

sinθ2sinθ2cosθ=kk2+1kk

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Answer 2

Answer:

Step-by-step explanation:

Given  

cosecθ+cotθ=k __(1)

we know cosec2θ−cot2θ=1

(cosecθ+cotθ)(cosecθ−cotθ)=k

⇒(k)(cosecθ−cotθ)=1

cosecθ−cotθ=k1 __(2)

subtract eq (2) from (1) we get

2cotθ=k−k1⇒sinθ2cosθ=kk2−1 __(3)

Add eq (1) & (2) we get

2cosecθ=k+k1

sinθ2=kk2+1 __(4)

Now from (3) & (4) we can write

sinθ2sinθ2cosθ=kk2+1kk