Math, asked by mayakashyap, 1 year ago

slove trigonometry ......

urgent please

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Answered by jawahaarabc143
3

sec4A - sec2A =2  1/cos4A - 1/cos2A =2  cos2A+ cos4A =2 cos4A * cos2A  cos2A + cos4A = cos6A + cos2A [cosC + cosD= 2 cos(C+D)/2 * cos(C-D)/2 ]  cos6A - cos4A = 0  2 sin(6A +4A)/2 sin(4A- 6A) =0  sin5A sin2A =0  so sin5A =0 & sin2A =0  or 5A = 0 & 2A = 0 =0  so A=npi/5& A=npi/2 where n =z [ A = 0 ]

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