Question

slove x^2 + x + 1= 0​

Answer 1

x^2+x+1=0

D=discriminant

D=(1-4(1)(1))

D<0

So for any value of x the equation is always positive

Now, by formula to find roots of quadratic equation we have,

x=[(-1)±{(1-4(1)(1)}^(1/2)]/2(1)

x=[-1±{(-3)}^(1/2)]/2

Hope it helps you :-)

Please mark it breainliest answer if you like it and follow me!!

Answer 2

Step-by-step explanation:

use b^2-4ac

1^2-4×1×1

-3

x=-b+-b^2-4ac÷2^1/2

x=-1+-(-3)÷2^1/2

x=-1+3÷2^1/2 or=-1-(-3)÷2^1/2

x=2^1/2 orx=x=1^1/2

x=2^1/2 orx=1