Question

slove x2+6x-7=0 quadratic equations by completing square ​

Answer 1

Hey mate!!

Here's your answer...

x²+6x-7=0

x²+6x=7

x²+6x+9=7+9       (adding 9 on both sides)

(x+3)²=16

x+3= ±4

x+3= 4    or    x+3= -4

x= 4-3     or  x= -4-3

x= 1         or    x= -7

Therefore, x= 1 or x= -7

Hope it helped you...

Answer 2

Question :

• Solve x²+6x-7=0 quadratic equations by completing square method

To Find :

• Value of x

Solution :

$\tt \implies {x}^{2} + 6x - 7 = 0 \\ \\ \tt \implies {x}^{2} + 6x = 7 \\ \\ \tt Adding \: 9 \: both \: side \\ \\ \tt \implies {x}^{2} + 6x + 9 = 7 + 9 \\ \\ \tt \implies {(x + 3)}^{2} = 16 \\ \\ \tt \implies x + 3 = \sqrt{16} \\ \\ \tt \implies x + 3 = \pm4 \\ \\ \tt \implies x + 3 = 4 \: \: \: \tt or \: \: \: x + 3 = - 4 \\ \\ \large \boxed{ \tt \blue{ x = 1 }}\: \: \: \tt or \: \: \: \boxed {\tt \green{ x = - 7}}$