Math, asked by Sandhyagupta54, 11 months ago

sloveee??????????????

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Answered by Mercidez
3
\large\blue{\boxed{Solution :\longrightarrow}}

\large\blue{\boxed{Given,}}

P = Rs \: \: 30000

T = 3 \: \: years

R = 6\% \: \: p.a.

\blue{\boxed{Now}}

\blue{\boxed{A = P \times (1 + \frac{R}{100} ) {}^{T} }}\\ \\ \: \: \: \: \: = Rs \: \: 30000 \times (1 + \frac{6}{100} ) {}^{3} \\ \\ \: \: \: \: \: = Rs \: \: 30000 \times \frac{106}{100} \times \frac{106}{100} \times \frac{106}{100} \\ \\ \: \: \: \: \: = Rs \: \: 35730.48

\blue{\boxed{CI = A - P }}\\ \\ \: \: \: \: \: = Rs \: \: (35730.48 - 30000) \\ \\ \: \: \: \: \: = Rs \: \: 5730.48

\red{\boxed{Hence, \: \: Ram \: \: have \: \: to \: \: have \: \: Rs}}
\red{\boxed{5730.48 \: \: \: after \: \: 3 \: \: years}}
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