Question

slowe the following differential equation xdy+ydx+xdy-ydx/x^2+y^2=0, given y=1 when x=1​

Answer 1

Answer:

d = 0

Step-by-step explanation:

xdy+ydx+xdy-ydx/x^2+y^2=0, given y=1 when x=1​

so putting the values

(1*d*1+1*d*1+1*d*1-1*d*1)/1*1+1*1 = (d+d+d-d)/1+1

                                                = (3d-d)/2

                                                = 2d/2 = d

so, d=0

do mark it as brainliest