Question

 small ball of mass m moving with speed v (<2gL−−−√) undergoes an elastic head on collision
with a stationary bob of identical mass of a simple pendulum of length L. The maximum height h, from
the equilibrium position, to which the bob rises after collision is.....​

Answer 1

Answer:

Here is ur answer

1) is correct

Since masses are same velocity will get exchanged after an elastic collison

For the block to complete a quarter circle it requires a minimum velocity of

$\sqrt{2gl}$

But according to question velocity is less than that so it will not be able to complete a quarter circle. So h(max) will be:mgH=1/2 mv^2,on solving we get H=v2/2g

Answer 2

Answer:mark me brainliest if it helps

Explanation: