Question

Small bob of a simple pendulum has mass m and length of pendulum is l. it isoscillating on a circular arc of angle theta in a vertical plane at the end of this arc and other ball of mass m is placed at rest momentum transport to this ball by the bob of pendulum isanyone solve!​

Answer 1

Answer:

zero

Explanation:

No momentum will be transferred because at extreme position the velocity of Bob is zero.

Answer 2

Given:  

Small bob of a simple pendulum has mass m and length of pendulum is l

To find:

Isoscillating on a circular arc of angle theta in a vertical plane at the end of this arc and other ball of mass m is placed at rest momentum transport to this ball by the bob of pendulum.

Solution:  

As we know that extreme position velocity of body will be zero so it means no momentum will be transferred to a ball of mass ‘m’ which is at rest

Mathematically

p=m$\times$v

Where :  

p=momentum

m=mass of a body

v=velocity

If velocity is zero then

p=m$\times$(0)

p=0