Small horizontal platform is undergoing vertical shm of amplitude one centimetre if mass of 50 gram placed on its surface is to remain continuously in contact with it,then the frequency of shm should be nearly equal to
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The frequency of SHM should be nearly equal to 5 Hz.
Given-
- Amplitude of vertical SHM = 1 cm
- Mass of object = 50 gram
We know that the mass of the object will remain in contact with the surface in case if
mg = mω²a
So, from the above equation
ω =
We know that ω = 2πf .So
2πf =
where f is the frequency
f = 1/2π
Substituting the values we get
f = 1/2π √980/1 = 5 Hz
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