Math, asked by desh26, 4 months ago

Small pieces of ice at 0°C are added to 0.35kg of water. The initial temperature of the water is 24.5°C. The temperature of the water decreases to 0°. The water loses 35000 J of thermal energy as it cools. All of the ice added to the water melts. The specific latent heat of fusion of ice is 3.3 × 10 power 5 J/kg. Calculate the specific heat capacity of water and the mass of ice added to the water​

Answers

Answered by sunitadhaka468
2

Answer:

Small pieces of ice at 0°C are added to 0.35kg of water. The initial temperature of the water is 24.5°C. The temperature of the water decreases to 0°. The water loses 35000 J of thermal energy as it cools. All of the ice added to the water melts. The specific latent heat of fusion of ice is 3.3 × 10 power 5 J/kg. Calculate the specific heat capacity of water and the mass of ice added to the water

Step-by-step explanation:

Small pieces of ice at 0°C are added to 0.35kg of water. The initial temperature of the water is 24.5°C. The temperature of the water decreases to 0°. The water loses 35000 J of thermal energy as it cools. All of the ice added to the water melts. The specific latent heat of fusion of ice is 3.3 × 10 power 5 J/kg. Calculate the specific heat capacity of water and the mass of ice added to the water

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