Question

small table weighing 40 N stands on four legs, each having an area of 0.001m2 what is the pressure of the table on the floor?

Answer 1

Given

A small table weighing 40 N stands on four legs, each having an area of 0.001 m²

To Find

What is  the pressure of the table on the floor

Solution

We know that

$\rm \longrightarrow P=\dfrac{F}{A}$

Here

• P = Pressure
• F = Force
• A = Area

Units

• P = Newton/square metre (N/m²)
• F = Newton (N)
• A = square metre (m²)

According to the question

We are asked to find the pressure of the table on the floor

Therefore

We must find "P"

Given that

A small table weighing 40 N stands on four legs, each having an area of 0.001 m²

Hence

• F = 40 N
• A = 0.004 m² [four legs]

Substituting the values

We get

$\rm \longrightarrow P=\dfrac{40}{0.004} \ N/m^{2}$

Therefore

$\rm \longrightarrow P=10000\ N/m^{2}$

Hence

Pressure of the table on the floor = 10000 N/m²

Answer 2

Answer:

Given :-

↦ A small table weighing 40 N stands on four legs, each having an area of 0.001 m²

Find Out :-

↦ Pressure of the table on the floor.

Formula Required :-

We know that,

↦ $\underline{\mathcal{\blue{ Pressure\: =\: \dfrac{Force}{Area}}}}$

Required Solution :-

Given that :

➛ Force = 40 N

Now, there are four legs means four area,

Then, area of each legs = 0.001 m²

➛ Area of four legs = 4 × 0.001 = 0.004 m²

ATQ,

➡ Pressure = $\dfrac{40 \times 1000}{4}$

➡ Pressure = $\dfrac{40000}{4}$

➦ Pressure = ${\boxed{\boxed{\sf{\red{10000\: m²}}}}}$

$\therefore$ $\small{\green{\bold{\underline{Pressure\ of\ the\ table\ on\ the\ floor\ is\ 10000\ m².}}}}$