Smaller arc has a radius of 5 cm and the
larger arc has a radius of 8 cm. The
central angle for both the arcs is 90°
Find the perimeter of the shape.
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Answer:
lenth of larger arc=
\frac{2\pi \:r}{4} = \frac{2 \times \pi \times 9}{4} = 4.5\pi42πr=42×π×9=4.5π
length of smaller arc=
\frac{2\pi \: r}{4} = \frac{2 \times \pi \times 6}{4} = 3\pi \: cm42πr=42×π×6=3πcm
thickness=9-6=3cm
perimeter of shape = lenth of larger arc +lenth of smaller arc + 2×thickness
=4.5π+3π+2×3
=7.5π+6
=29.57cm
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