Question

smallest 4 digit number such that when it is divided by 12, 18, 21 and 28, it leaves remainder 3 in each case.

Answer 1

Step-by-step explanation:

LCM of 12,12,21,28 is 252

smallest 4 digit = 252*4 = 1008

leaves reminder 3 = 1008+3 =1011

Answer 2

Answer:

1011

Step-by-step explanation:

Find the prime factors:

12 = 2² x 3

18 = 2 x 3²

21 = 3 x 7

28 = 2² x 7

Find the LCM:

LCM = 2² x 3² x 7 = 252

Find the smallest 4 digit number that is a multiples of 252:

Smallest 4 digit number = 1000

1000 ÷ 252 = 3.97 ≈ 4 (round up)

smallest 4 digit number that is a multiples of 252 = 252 x 4 = 1008

It has a reminder of 3

⇒ The number is 1008 + 3 = 1011

Answer: The number is1011

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