smallest internuclear distance is found in
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solid
Explanation:
because molecules are tightly packed
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Smallest internuclear distance is found in (a) O₂ (b) O₂²⁺ (c) O₂⁻ (d) O₂²⁻
Answer:
Smallest internuclear distance is found in O₂²⁺ .
Explanation:
- Internuclear distance is the distance between two nuclei in a molecule.
- The length of a bond is inversely proportional to the bond order; the higher the bond order, the shorter the length of the bonds. This occurs as the higher bond order causes an increased amount of attraction between the atoms, resulting in a shortened bond.
- In O₂, the bond order = 2
- In O₂²⁺, the bond order = 3
- In O₂⁻ , the bond order= 1.5
- In O₂²⁻ , the bond order = 1
As the bond order in O₂²⁺ is highest, So its internuclear distance is smallest.
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