Question

Smallest no.that on division by 15 and 35 leave 2 as remainder in each case

Answer 1

The number which on division by 15 and 35 leaves a remainder 2 in both the cases is 107

107/15

Quotient = 7

Remainder 2

107/35

Quotient = 3

Remainder = 2

First find out the LCM of both 15 and 35

Lcm is 105

Now add two to the LCM obtained

That gives 105+2=107

So 107 is the smallest number which when divided by 15 and 35 leaves a remainder 2

Answer 2

Answer = LCM(15, 35) + 2
= 3×5×7 + 2 = 105+2= 107