Question

Smallest no. Which leaves remainder 8 and 12 when divided by 28 and 22

Answer 1

Answer:

The Answer is 204

Step-by-step explanation:

1) Subtract the remainders from the given numbers:

28-8 = 20

32 -12 = 20

Both of them give 20

2) Find the LCM of 28 and 32

28 = 2 × 2 × 7

32 = 2 × 2 × 2 × 2 × 2

LCM = 2 × 2 × 2 × 2 × 2 × 7 = 224

3) Smallest no: which leaves remainder 8 and 12 when divided by 28 and 32 = LCM -20 = 224 - 20 = 204

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