smallest number by which 1100 must be multiplied so it become a perfect cube root
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Answer:
1100÷2
550÷2
275÷5
55÷5
11
no factors of 1100= 2²*5²*11
we need, 2,5,11²
therefore, the required number= 2*5*11*11= 1210
hope this is the answer
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