Question

Smallest number by which 3807 may be multiplied so that the product is a perfect cube​

Answer 1

Answer:

Step-by-step explanation:

3807=3x3x3x3x47

=3^4 x 47^1

For a perfect cube the prime factorization will have powers as multiples of 3.

So here 3 has a power of 4. The next number to 4 which is a multiple of 3 is 6.

So we need to multiply the number with 3^(6-4) x 47^(3-1)

=3^2 x 47^2

=19881