Question

smallest number when decreased by 28 is exactly divisible by 408 and 528 is​

Answer 1

Answer:

First we need to find the L.C.M. of 520 and 468, since that will be the lowest number divisible both by 520 and 468. Then we need to reduce 17 from that number.

Prime factorisation of :-

520= 2 X 2 X 2 X 5 X 13 = 2^3 X 5 X 13

468 = 2 X 2 X 3 X 3 X 13= 2^2 X 3^2 X 13

So, L.C.M. = 2^3 X 5 X 13 X 3^2= 4680

So, the answer is 4680 - 17 = 4663.